MATH SOLVE

3 months ago

Q:
# Write the slope-intercept form of the equation that passes through the point (3,-2) and is parallel to the line y = -x - 5

Accepted Solution

A:

Answer:The equation of the line is y = -x + 1Step-by-step explanation:* Lets explain how to solve the problem- The slope-intercept form of the equation is y = mx + c, where m is the slope of the line and c is the y-intercept- To make this equation you need slope (m) and a point on the line to find the value of c- The parallel lines have same slopes* Lets solve the problem- The line is parallel to the line y = -x - 5∵ y = mx + c∵ The slope of the line y = -x - 5 is the coefficient of x∴ m = -1∵ Parallel lines have same slopes∴ The slope of the line is -1∴ the equation of the line is y = -x + c- To find c substitute x and y in the equation by the coordinates of any point lies on the line∵ The line passes through point (3 , -2)∵ y = -x + c∴ -2 = -(3) + c∴ -2 = -3 + c ⇒ add 3 for both sides∴ c = 1∴ The equation of the line is y = -x + 1