an equation in slope-intercept form for the line that passes through (4,-4) and is parallel to 3+4x=2y-9

Answer:[tex]\large\boxed{y=-\dfrac{1}{2}x-2}[/tex]Step-by-step explanation:[tex]\text{The slope-intercept form:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\======================[/tex][tex]\text{If}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\ \text{are\ parallel, then}\ m_2=-\dfrac{1}{m_1}\\===========================[/tex][tex]\text{We have the equation of a line:}\ 3+4x=2y-9.\\\text{Convert it to the slope-intercept form:}\\\\2y-9=3+4x\qquad\text{add 9 to both sides}\\\\2y=12+4x\qquad\text{divide both sides by 2}\\\\y=6+2x\\\\y=2x+6\to m_1=2\\\\\text{therefore}\ m_2=-\dfrac{1}{2}\\\\\text{We have the equation:}\ y=-\dfrac{1}{2}x+b\\\\\text{Put the coordinates of the given point (4, -4) to the equation:}\\\\-4=-\dfrac{1}{2}(4)+b\\\\-4=-2+b\qquad\text{add 2 to both sides}\\\\-2=b\to b=-2\\\\\text{Finally we have the equation:}\ y=-\dfrac{1}{2}x-2[/tex]